# Kanodia book for gate electrical pdf

From where can I download RK Kanodia for electrical engineering in PDF Where do I download electrical engineering text books in PDF format for free?. GATE. ELECTRICAL ENGINEERING. Vol 1 of 4. RK Kanodia. Ashish Murolia This book is published with the understanding that NODIA & COMPANY and its. Best GATE MCQ For Electrical Engineering Vol-3 book available at Nodia Publications. click to download pdf Authors, R K Kanodia & Ashish Murolia.

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MCQ 1. The value of n for which d: Equation 1 10x2 sin x1 - 0. Then the r. In succession, two balls are randomly and removed form the box. The following statement is true. Consider the event of at least two people in the room being born on the same date of the month, even if in different years, e. What is the smallest N so that the probability of this event exceeds 0. A Q will have four linearly independent rows and four linearly independent columns B Q will have four linearly independent rows and five linearly independent. Then the function has A only one minimum B only tow minima C three minima D three maxima.

Network theorems: Steady state sinusoidal analysis using phasors. Linear constant coefficient differential equations; time domain analysis of simple RLC circuits, Solution of network equations using Laplace transform: State equations for networks. Network analysis techniques; Network theorems, transient response, steady state sinusoidal response; Network graphs and their applications in network analysis; Tellegens theorem. Two port networks; Z, Y, h and transmission parameters. Combination of two ports, analysis of common two ports. Network functions: Transmission criteria: Elements of network synthesis. The linear network in the figure contains resistors and dependent sources only. Which of the following equation is true for IL?

The values of I1 , I2 and I 3 are respectively. In the circuit below, current I is equal to sum of two currents I1 and I2. What are the values of I1 and I2? A network consists only of independent current sources and resistors.

If the values of all the current sources are doubled, then values of node voltages A remains same B will be doubled C will be halved D changes in some other way.

## GATE QUESTIONS BANK AND QUICK REFRESHER GUIDE FILES - SURYAS TECHNO WORLD

Consider a network which consists of resistors and voltage sources only. If the values of all the voltage sources are doubled, then the values of mesh current will be A doubled B same C halved D none of these. For the circuit shown in the figure the Thevenin voltage and resistance seen from the terminal a -b are respectively.

In the following circuit, Thevenin voltage and resistance across terminal a and b respectively are. The value of RTh and VTh such that the circuit of figure B is the Thevenin equivalent circuit of the circuit shown in figure A , will be equal to.

Common Data for Q. Consider the two circuits shown in figure A and figure B below. The value of Thevenin resistance across terminals a -b of figure A and figure B respectively are A zero, 3 B 9 , 16 C 2 , 3 D zero, Statement for linked Questions 30 and Consider the circuit shown in the figure. The equivalent Thevenin voltage across terminal a -b is A For a network having resistors and independent sources, it is desired to obtain Thevenin equivalent across the load which is in parallel with an ideal current source.

Then which of the following statement is true? A The Thevenin equivalent circuit is simply that of a voltage source. B The Thevenin equivalent circuit consists of a voltage source and a series resistor.

C The Thevenin equivalent circuit does not exist but the Norton equivalent does exist. D None of these. The Thevenin equivalent circuit of a network consists only of a resistor Thevenin voltage is zero. Then which of the following elements might be contained in the network? A resistor and independent sources B resistor only C resistor and dependent sources D resistor, independent sources and dependent sources.

The Thevenin voltage and resistance of the unknown circuit are respectively. In the circuit shown below, the Norton equivalent current and resistance with respect to terminal a -b is. What are the values of equivalent Norton current source IN and equivalent resistance RN across the load terminal of the circuit shown in figure? For a network consisting of resistors and independent sources only, it is desired to obtain Thevenins or Nortons equivalent across a load which is in parallel with an ideal voltage sources.

Consider the following statements:. Thevenin equivalent circuit across this terminal does not exist. The Thevenin equivalent circuit exists and it is simply that of a voltage source. The Norton equivalent circuit for this terminal does not exist. For a network consisting of resistors and independent sources only, it is desired to obtain Thevenins or Nortons equivalent across a load which is in series with an ideal current sources.

Consider the following statements 1. Norton equivalent across this terminal is not feasible. Norton equivalent circuit exists and it is simply that of a current source only.

Thevenins equivalent circuit across this terminal is not feasible. In the circuit below, if RL is fixed and Rs is variable then for what value of Rs power dissipated in RL will be maximum? For the circuit of figure, some measurements were made at the terminals a -b and given in the table below. For the linear network shown below, V -I characteristic is also given in the figure. The value of Norton equivalent current and resistance respectively are.

A practical DC current source provide 20 kW to a 50 load and 20 kW to a load. The maximum power, that can drawn from it, is A Statement for Linked Questions In the following circuit, some measurements were made at the terminals a , b and given in the table below. The value of A in ohm and B in volt respectively are.

The V -I relation for the circuit below is plotted in the figure. The maximum power that can be transferred to the load RL will be. The value of is.

A network N feeds a resistance R as shown in circuit below. Let the power consumed by R be P. If an identical network is added as shown in figure, the power consumed by R will be. A certain network consists of a large number of ideal linear resistors, one of which is R and two constant ideal source.

The power consumed by R is P1 when only the first source is active, and P2 when only the second source is active. If both sources are active simultaneously, then the power consumed by R is B P1! P2 A P1! P2 C P1! If the 60 resistance in the circuit of figure A is to be replaced with a current source Is and shunt resistor as shown in figure B , then magnitude and direction of required current source would be. The maximum power that can be transferred to the load resistor RL from the current source in the figure is.

Common data for Q. In the circuit given below, viewed from a -b, the circuit can be reduced to an equivalent circuit as. A 10 volt source in series with 2 k resistor B resistor only C 20 V source in series with The power absorbed by load resistance RL is shown in table: In the following circuit the value of open circuit voltage and Thevenin resistance at terminals a, b are. With 10 V dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed: The maximum power that can be transferred to the load resistor RL from the voltage source in the figure is.

For the circuit shown in the figure, Thevenins voltage and Thevenins equivalent resistance at terminals a -b is. The value of R in ohms required for maximum power transfer in the network shown in the given figure is. Superposition theorem is NOT applicable to networks containing A nonlinear elements B dependent voltage sources C dependent current sources D transformers. For the circuit shown in figure, the Norton equivalent source current value and and its resistance is.

Viewed from the terminals A-B , the following circuit shown in figure can be reduced to an equivalent circuit of a single voltage source in series with a single resistor with the following parameters. A 5 volt source in series with 10 resistor B 1 volt source in series with 2.

For the circuit given above, the Thevenins resistance across the terminals A and B is A 0. For the circuit given above, the Thevenins voltage across the terminals A and B is A 1. The current through the resistance is. In the circuit given below, the value of R required for the transfer of maximum power to the load having a resistance of 3 is. For the circuit shown in figure R is adjusted to have maximum power transferred to it. The maximum power transferred is. In full sunlight, a solar cell has a short circuit current of 75 mA and a current of 70 mA for a terminal voltage of 0. The Thevenin resistance of the solar cell is A 8 B 8. The source network S is connected to the load network L as shown by dashed lines.

The power transferred from S to L would be maximum when RL is. We solve this problem using principal of linearity. Linearity does not apply to power calculations. For, SOL 5. Option C is correct. Option D is correct. Option B is correct. The circuit has 3 independent sources, so we apply superposition theorem to obtain the voltage drop.

Due to 16 V source only: Using voltage division 9. The problem may be solved by applying a node equation at the top node. We solve this problem using superposition. Due to 9 A source only: Open circuit 6 A source. Open circuit 9 A source. The problem may be solved by transforming both the current sources into equivalent voltage sources and then applying voltage division. SOL 5.

## GATE CLOUD Network Analysis by R K Kanodia

Using super position, we obtain I. Due to 10 V source only: Open circuit 5 A source. From superposition theorem, it is known that if all source values are doubled, then node voltages also be doubled.

Option A is correct. From the principal of superposition, doubling the values of voltage source doubles the mesh currents. Applying superposition, Due to 6 V source only: Open circuit 2 A current source. This problem may be solved by using a single KVL equation around the outer loop.

Applying superposition, Due to 24 V source only: Open circuit 2 A and short circuit 20 V source. We can see that current in the middle 4 resistor is I 2 , therefore I can be obtained by applying KVL in the bottom left mesh.

Try to solve the problem by obtaining Thevenin equivalent for right half of the circuit. Using source transformation of 4 A and 6 V source.

We know that source transformation is applicable to dependent source also. Combining the parallel resistance and adding the parallel connected current sources. We apply source transformation as follows. Transforming 3 mA source into equivalent voltage source and 18 V source into equivalent current source. Thevenin voltage: Open circuit voltage The open circuit voltage between a -b can be obtained as 2.

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To obtain Thevenins resistance, we set all independent sources to zero i. Set all independent sources to zero i. We obtain Thevenins resistance across a -b and then use source transformation of Thevenins circuit to obtain equivalent Norton circuit.

The current source connected in parallel with load does not affect Thevenin equivalent circuit. Thus, Thevenin equivalent circuit will contain its usual form of a voltage source in series with a resistor.

The network consists of resistor and dependent sources because if it has independent source then there will be an open circuit Thevenin voltage present. Current I can be easily calculated by Thevenins equivalent across 6. Open circuit voltage. The problem can be solved easily by a single node equation.

Take the nodes connecting the top 4 , 3 V and 4 as supernode and apply KCL.

## GATE Electrical Solved paper - R K Kanodia

Thevenin Resistance: Direct Method: Since dependent source is present in the circuit, we put a test source across a -b to obtain Thevenins equivalent. We obtain Thevenins equivalent across R. Norton current: Short circuit current The Norton equivalent current is equal to the short-circuit current that would flow when the load replaced by a short circuit as shown below.

The voltage across load terminal is simply Vs and it is independent of any other current or voltage. The Norton equivalent does not exist because of parallel connected voltage source.

Thus, effect of all other component in the network does not change IN. In this case Thevenins equivalent is not feasible because of the series connected current source.

By source transformation of both voltage sources. Thevenin voltage open circuit voltage may be obtained using node voltage method also. Do not get confused with maximum power transfer theorem. We solve this problem using maximum power transfer theorem.

First, obtain Thevenin equivalent across RL. In Stock Download Sample Chapter. Special price: Rs Your Name. Your Question. Enter the code in the box below. Write a review Your Name. Your Review Note: HTML is not translated! The book is featured as The book is categorized into Units Subjects and each Unit is sub-divided into Chapters Chapter organization for each Unit Subject is very constructive and covers the complete syllabus Each Chapter contains an average of 40 questions and there are approximate problems for each subject The questions match to the level of GATE examination Solutions are well-explained, tricky and consume less time.

Solutions are presented in such a way that it enhances your fundamentals and problem solving skills There are a variety of problems on each topic Gate Previous Year Solved Questions has been added for each subject Engineering Mathematics and General Aptitude GA are also included in the book Included Numerical Type Questions.

Basic Concept 2. Basic Laws 3. Graph Theory 4. Nodal and Loop Analysis 5. Circuit Theorems 6. Inductor and Capacitor 7. Second Order Circuit 9. Sinusoidal Steady State Analysis AC Power Analysis Three-phase Circuits Magnetically Coupled Circuits Frequency Response Circuit Analysis Using Laplace Transform Coulomb's Law and electric Field Intensity 2. Electric Potential 4. Dielectrics and Capacitance 5. Steady Magnetic Field 6.